Question

I ran into this in an old math textbook. Any solvers?
. One man and two boys can do in 12 days certain work that could be done in 6 days by three men and one boy. How long would it take one man to do it?

Answer 1

Answer:

Step-by-step explanation:

M + 1B = 2M + 4B

ie 1M = 3B so one man does the same work as three boys.

Therefore five boys (equivalent to one man and two boys) would take twelve days to do the job. One boy would take five times as long so it would take one boy sixty days to do the job.

Three boys would take one third as long so they would take 20 days and one man is equivalent to three boys so one man will take 20 days