Question

I read 4/9 of a book on one day and 3/5 of the remaining next day. If 100 pages of the book were still left unread, how many pages did the book contain .​

Answer 1

Answer:

150 pages

Step-by-step explanation:

(4/9)th of a book is read on first day. (3/5)th part of the remaining is read on next day. These remaining pages are those 100 pages of the book which were left unread. Hence the book contains a total of 150 pages.

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Answer 2

$\bigstar\boxed{\large\bf\red{\leadsto The \:book\: contain\:150 \:pages}}$

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$\large\bf\underline{Given:}$

• ➨ I read $\bf{\frac{4}{9}}$ pages of a book one day
• ➨ And $\bf{\frac{3}{5}}$ the remaining day
• ➨ 100 pages of the book are remaining still unread

$\large\bf\underline{To\:Find:}$

• ➠ Total number of pages in book

❒ Let the total number of pages in book be x

• ➨ $\bf{\frac{4}{9}}$pages of book were read on first day , so number of pages read on this day :

ㅤㅤㅤㅤㅤ$\bf{:\implies \frac{4}{9}\times x}$

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• ➨ And number of pages remaining :

ㅤㅤㅤㅤㅤ$\bf{:\implies x- \frac{4x}{9}}$

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ㅤㅤㅤㅤㅤ$\bf{:\implies \frac{5x}{9}}$

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• ➨ $\bf{\frac{3}{5}}$ part of the remaining book was read on next day , so number of pages read on next day :

ㅤㅤㅤㅤㅤ$\bf{:\implies \frac{3}{\cancel{5}}\times\frac{\cancel{5}x}{9}}$

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ㅤㅤㅤㅤㅤ$\bf{:\implies \frac{x}{3}}$

• ➨ And number of pages remaining unread :

ㅤㅤㅤㅤㅤ$\bf{:\implies x-\frac{x}{3}}$

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ㅤㅤㅤㅤㅤ$\bf{:\implies \frac{2x}{3}}$

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• ➨ $\bf{\frac{2x}{3}}$ is the number of pages which were left unread

ㅤㅤㅤㅤㅤ$\bf{\longrightarrow \frac{2x}{3}=100}$

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ㅤㅤㅤㅤㅤ$\bf{\longrightarrow 2x=100\times 3}$

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ㅤㅤㅤㅤㅤ$\bf{\longrightarrow x= \frac{100}{3}}$

ㅤㅤㅤㅤㅤ$\bf{\longrightarrow x = 150}$

$\underline{\boxed{\bf{ Hence,\:there \:are \:150\:pages\:in\:the\:book}}}$

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