Question

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How step 2 was done from step1.

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Answer 1

Answer:

Given:

2 steps of a particular Equation solution had been provided

To explain:

How 2nd step was obtained from 1st step.

Explanation:

1st step (as per book)

$|R| = \sqrt{ {(F1)}^{2} + {(F2)}^{2} { \cos(\theta) }^{2} + 2(F1)(F2)\cos(\theta) + {(F2)}^{2} { \sin(\theta) }^{2} }$

Now, we take (F2)² common between the F2 containing terms in the 1st step.

$|R| = \sqrt{ {(F1)}^{2} + 2(F1)(F2)\cos(\theta) + {(F2)}^{2} [ { \sin(\theta) }^{2} + { \cos(\theta)}^{2} ]} \:$

Now we know that :

sin²(θ) + cos²(θ) = 1

So we get the next step as :

$|R| = \sqrt{ {(F1)}^{2} + 2(F1)(F2)\cos(\theta) + [ {(F2)}^{2} \times 1 ]}$

This is same as the 2nd step as given in the book.