Question

(i) sec 0(1-sin O)(sec + tan 6) =1​

Answer 1

Answer:

note that,

$\frac{1}{ \cosθ } = \secθ \\ { \sec }^{2} θ - { \tan }^{2} θ = 1 \\ \frac{ \sinθ }{ \cosθ } = \tanθ$

your answer is given in the above picture☺️