Question

The diagonal of a rectangular field ABCD is (x + 9) m and the sides are (x + 7) m and xm.find the value of x
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Answer 1

Answer:

acc. to question: (x+9) =√[(x+7) ^2 +(x) ^2]

(x+9) =√x^2+49+14x +x^2

(x+9) ^2=2x^2 +49+14x

x^2+81+18x= 2x^2+49+14x

32 + 4x = x^2

x^2 -4x-32 =0

x^2 -8x+4x -32 =0

x(x-8) +4(x-8) =0

x+4 =0x=-4

x-8 =0;x=8

Since x can't be negative x= 8