i) The argument of i^17 is ?
ii) The solution set of the inequality 2/x-3 < 0 is ?
iii) If SinΦ + CosΦ = 1 then the value of Sin2Φ is ?
Answers
Answered by
45
Step-by-step explanation:
i)
= > i^17 = > ( i^16 )i = > ( 1 )i = > i
= > 0 + 1i
Since the given point lies on y axis, thus argument of this number is π / 2.
ii)
= > 2 / ( x - 3 ) < 0
= > ( x - 3 )^2 × ( 2 ) / ( x - 3 ) < 0
= > 2x - 6 < 0
= > x < 3
Solution set is { ...- 1 , 0 , 1 , 2 } { x € Z }
iii)
= > sinA + cosA = 1
= > sin^2 A + cos^2 A + 2sinAcosA = 1 { sq. on both sides }
= > 1 + sin2A = 1 { sin^2 B + cos^2 B = 1 , 2sinAcosA = sin2A }
= > sin2A = 0
Answered by
31
Step-by-step explanation:
(i) Argument of
Clearly, it lies on the Y axis.
Therefore, it's argument is
(ii) Solution set of inequality 2/(x-3) < 0
Hence, solution set is {.....-5, -4....0,1,2}
where, x € Z
(iii) Value of
Squarring both the sides, we get
Hence,
Concept Map :-
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