Question

i) The cross-sectional area of a bar magnet 10 cm long is 1.2 cm². If the magnetic
moment of the magnet is 2.4 A m², find its magnetization.
iontimeter wire depend? (1​

Answer 1

Explanation:

M

net

=2Am

2

,I=10cm=10×10

−2

m

Area of cross section = 4cm

2

=4×10

−4

m

2

Then,

Magnetization (M

z

)=

V

M

net

[V= l × cross-sectional area V=10×10

−2

×4×10

−4

V=4×10

−5

m

3

]

⇒M

z

=

4×10

−5

2

M

z

=5000

m

A

Answer 2

Answer:

Magnetization is  0.2*10^6

Explanation:

here, moment of magnet, N = 2.4Am^2

length of magnet, l = 10cm

cross section of magnet, A =1.2cm^2

volume of magnet, V= Al=  1,2*10 = 12cm^3= 12*10^-6m^3

mow magnetization, M= N/V

M= 2.4/12*10^-6

M= 0.2*10^6