(i) The following frequency distribution table shows marks obtained by 180 students in Me
examination :
Marks
Number of Students
0-10
25
10 - 20
sox
20 - 30
30
30 - 40
2x ho
40 - 50
65
Find the value of x.
M = 180
Also draw a histogram representing the above information.
Answers
The value of x is 20.
The histogram representing the above information is as shown below.
Given,
Marks Number of Students
0 - 10 25
10 - 20 x
20 - 30 30
30 - 40 2x
40 - 50 65
Total number of students M = 180
So, we have,
25 + x + 30 + 2x + 65 = 180
120 + 3x = 180
3x = 180 - 120
3x = 60
x = 20
Therefore, the value of x is 20.
Marks Number of Students
0 - 10 25
10 - 20 x = 20
20 - 30 30
30 - 40 2×20 = 40
40 - 50 65
Therefore, the complete data is,
Marks Number of Students
0 - 10 25
10 - 20 20
20 - 30 30
30 - 40 40
40 - 50 65
The histogram representing the above information is as shown below.
