Question

(vi) The number of moles of methyl iodide required to prepare
tetramethylammonium iodide from 1 mole of methyl amine
is/are :
​

Answer 1

Answer:(c) 3

Explanation:

Answer 2

3 moles of methyl iodide is required.

Explanation:

• The reactant is methyl amine.

• The reagent is methyl iodide.

• So with the first mole of methyl iodide, it forms the dimethyl anime and hydrogen iodide.

• With the second mole, it forms trimethylamine and hydrogen iodide again.

• With the third mole, it forms the tetramethylamine iodide.

• For more information about methyl amine,

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