Question

i) The product of two numbers is 120. If their H.C.F. is 6 what is their L.C.M.
(ii) Find the smallest number which, on being added 23 to it, is exactly divisible by 32, 36, 48 and 96.
(iii) Find the least length of a rope which can be cut into whole number of pieces of lengths 45 cm, 75 cm and 81 cm.
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Answer 1

i)120=6×LCM

LCM=120÷6=20

Answer 2

Step-by-step explanation:

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