Math, asked by suryanshthakur0122, 10 months ago

i) There are three buckets containing 24 L, 36 L and 48 L of milk. Find the capacity of
smallest bucket that can measure the milk in the three buckets.​

Answers

Answered by kumudhakshid
13

Answer:

Step-by-step explanation:

We are asked to find hcf in this case thus follow these steps:

2×2×2×3=24

2×2×3×3=36

2×2×2×2×3=48

Therefore we find 2×2×3=12 as the hcf(24,36,48) hence the smallest that can measure milk in the three buckets is 12ml

Hope this helps you!

Answered by priyasipriyadarsani
1

First find the HCF of the following numbers

24 = 2×2×2×3

36 = 2×2×3×3

48 = 2×2×2×2×3

common = 2,2,3

HCF = 2×2×3

= 12

answer = the smallest capacity of the three buckets is 12 ml

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