I tried but its wrong...answer is (0,9).
Question 6
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Hi,find the answer in the attached image.
Hope it helps...
Hope it helps...
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rakshankmr:
you used distance formula?
Actually, my elder cousin answered this and now he has left.So, I don't know, sorry. ...
yes
ohk....thanks
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y axis mean x coordinate will be 0
So, consider the point be C (0,y)
Since
AC=BC
So, by distance formulae and cancelling the under-roots
(6-0)^2+(5-y)^2=(-4-0)^2+(3-y)^2
36+25+y^2-10y=16+9+y^2-6y
10y-6y=36+25-16-9
4y=36
y=9
So, point is (0,9)
PLZ MARK IT AS BRAINLIEST.
So, consider the point be C (0,y)
Since
AC=BC
So, by distance formulae and cancelling the under-roots
(6-0)^2+(5-y)^2=(-4-0)^2+(3-y)^2
36+25+y^2-10y=16+9+y^2-6y
10y-6y=36+25-16-9
4y=36
y=9
So, point is (0,9)
PLZ MARK IT AS BRAINLIEST.
what formula are you using?
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