if the points p(a,-11), q(5, b), r(2, 15) and s(1, 1) are the vertices of a parallelogram PQRS .find the value of a and b.
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Answered by
18
the difference between abscissa of p and q will be equal to the difference between the abscissa of q and s and the same goes for the ordinate between p and r, and q and s
a-5=2-1
a=6
b-1=-11-15
b=-25
Answered by
29
Answer:
Step-by-step explanation:
Slope of PQ=SR
(a-5)/(-11-b)=(1–2)/(1–15)
a= -(b+11)/14 +5 …..(1)
Slope PS=QR
(a-1)/(-11–1)=(5–2)/(b-15)
(b-15)((b+11)/14–4)=36
(b-15)(b-45)=36*14
b^2–60b+171
Sol : b = (60+/-54)/2
b=3, a=4,
b=57, a=69/7
I hope you are happy!!!!
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