I've been searching for a few answers after maths exam. Can smone please help me out... (Q.15)
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α=-b/a=4
β=c/a=3
α^4=156 ,α^2=16
β^4=81, β^2=9
therefore
(α^4β^2+α^2β^4)=256*9+81*16
=2304+1296=3600
MARK BRAINLIEST
FOLLOW.
F12345:
Sum of zeroes = -b/a
I don't think alpha= 4 & beet a =3. Can u pls verify and tell me
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