I want answer of Question 34,35,36
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34) 0.3x - 0.8 + 0.2x = 0.2 - 0.5x
=> 0.5x - 0.8 = 0.2 - 0.5x
=> 0.5x + 0.5x = 0.2 + 0.8
=> 1x = 1
=> x = 1
35) by cross multiplication,
=> 2(9 - 3x) = 5(7 - 4x)
=> 18 - 6x = 35 - 20x
=> 20x - 6x = 35 - 18
=> 14x = 17
=> x = 17/14
36) in attachment
____________
hope this helps!
34) 0.3x - 0.8 + 0.2x = 0.2 - 0.5x
=> 0.5x - 0.8 = 0.2 - 0.5x
=> 0.5x + 0.5x = 0.2 + 0.8
=> 1x = 1
=> x = 1
35) by cross multiplication,
=> 2(9 - 3x) = 5(7 - 4x)
=> 18 - 6x = 35 - 20x
=> 20x - 6x = 35 - 18
=> 14x = 17
=> x = 17/14
36) in attachment
____________
hope this helps!
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hiii dear_______
___________________________
good evening
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here's your answer________________________________________________
Q.34
O.3x - (0.8-0.2x) = 0.2-0.5x
0.5x+0.3x + 0.2x = 0.2 + (0.8)
1.0 x = 1.0
x = 1.0/1.0 = 1
x = 1
Q.35
(7-4x)/(9-3x) = 2/5
(7-4x)*5 = (9-3x)*2
35 - 20x = 18 - 6x
35 - 18 = 20x - 6x
17 = 14x
x = 17/14
Q.36
=√ [248 + √(52 + 12)]
= √ (248 + √64
=√ (248 + 8)
= √256
= 16
___________________________
good evening
___________________
here's your answer________________________________________________
Q.34
O.3x - (0.8-0.2x) = 0.2-0.5x
0.5x+0.3x + 0.2x = 0.2 + (0.8)
1.0 x = 1.0
x = 1.0/1.0 = 1
x = 1
Q.35
(7-4x)/(9-3x) = 2/5
(7-4x)*5 = (9-3x)*2
35 - 20x = 18 - 6x
35 - 18 = 20x - 6x
17 = 14x
x = 17/14
Q.36
=√ [248 + √(52 + 12)]
= √ (248 + √64
=√ (248 + 8)
= √256
= 16
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