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area of shaded region = ar(∆ABC)+ar(semicircle with diameter AC)-ar(sector with radius BC)
ar(∆ABC)= 1/2*28*21
= 14*21
= 294cm²
AC=√BC²+AB²
=√21²+28²
= √441+784
=√1225
= 35
ar(semi circle) = πr²/2
= 22*35*35/7*2
= 11*5*35
= 1925cm²
ar(sector) = 90/360*22/7*21*21
= 22*3*21/4
=11*3*21/2
= 693/2
= 346.5
ar(shaded region)= 294+1925-346.5
=1872.5cm²
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