Math, asked by saifullahmemon2014, 1 month ago

i want correct answer and explanation.​

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Answered by chanamaneni123
0

Answer:

last year:

lets take Shoaib age as 4x

and Basit age is x

4x+1+x+1 adding +1 for both years as an year is increased

that is 5x+2=57

5x=55

x=55/5

x=11

Answered by BrainlyArnab
2

"

 \huge \frak \purple{b)12}

Step-by-step explanation:

Q.

Last year, Shoaib was 4 times as old Basit. This year sum of their ages is 57. How old Basit now ?

.

Solution -

Let last year Basit's age = x,

his age this year = x + 1

Shoaib's age last year = 4×basut = 4x

his age this year = 4x + 1

.

Sum of their ages this year = 57

=> 4x + 1 + x + 1 = 57

=> 4x + x + 1 + 1 = 57

=> 5x = 57-2

=> 5x = 55

=> x = 55/5

=> x = 11

.

x = Basit's age last year = 11

his age this year = x + 1 = 11+1 = 12

.

hope it helps.

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