i want correct answer and explanation.
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Answer:
last year:
lets take Shoaib age as 4x
and Basit age is x
4x+1+x+1 adding +1 for both years as an year is increased
that is 5x+2=57
5x=55
x=55/5
x=11
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Step-by-step explanation:
Q.
Last year, Shoaib was 4 times as old Basit. This year sum of their ages is 57. How old Basit now ?
.
Solution -
Let last year Basit's age = x,
his age this year = x + 1
Shoaib's age last year = 4×basut = 4x
his age this year = 4x + 1
.
Sum of their ages this year = 57
=> 4x + 1 + x + 1 = 57
=> 4x + x + 1 + 1 = 57
=> 5x = 57-2
=> 5x = 55
=> x = 55/5
=> x = 11
.
x = Basit's age last year = 11
his age this year = x + 1 = 11+1 = 12
.
hope it helps.
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