i want full calcultions of this question
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size = radius = 0.5 À = 0.5 × 10^-10m = 5×10^-11
it is in a shape of spherical according to the Bohr's law .
volume of one hydrogen atom = V = ?
V = 4πr³/3
V = 4×3.14×(5×10^-11)³/3
V = 4.18×125×10^-33
V = 522.5×10^-33
one moles contains avogadro numbers i.e 6.022×10^23 atoms .
volume of 1 mol atoms of H
= 6.022×10^23×522.5×10^-33
= 3146.5 × 10^-10
= 3.1465 × 10^-7 m³
so answer is 3.1465 × 10^-7 m³
it is in a shape of spherical according to the Bohr's law .
volume of one hydrogen atom = V = ?
V = 4πr³/3
V = 4×3.14×(5×10^-11)³/3
V = 4.18×125×10^-33
V = 522.5×10^-33
one moles contains avogadro numbers i.e 6.022×10^23 atoms .
volume of 1 mol atoms of H
= 6.022×10^23×522.5×10^-33
= 3146.5 × 10^-10
= 3.1465 × 10^-7 m³
so answer is 3.1465 × 10^-7 m³
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