Question

I want solution of this question.​

Answer 1

Answer:

let Ram's marks = x

let Shyam's marks = y

let Anita marks = z

x + y + z = 128 ------ (1)

x = y + 8

so y = x - 8

z = x + 4

substitute these values in (1)

x + x - 8 + x + 4 = 128

3x - 4 = 128

3x = 128 + 4

3x = 132

x = 132/3

x = 44

Ram got 44 marks

Answer 2

Answer:

hope this is help full

answer is 44

Step-by-step explanation:

let shyam marks would be 'x'

let ram marks would be x+8

let  anil marks would be x+8+4=    x+12

. x+(x+8)+(x+12)=128

(3x)+(8+12)=128

3x+20=128

3x=128-20

3x=108

x=108/3

x=36

shyam marks is 36

ram marks is (36+8)=44

anil marks is (44+4)=48   (therefore anil got 4 marks more than ram)