Question

i want solution of this question

Answer 1

Here is the answer check it out!

Answer 2

m th term is 1/n

tm => a + (m -1)d = 1/n  -----------------(1)

n th term is 1/m

tn => a + (n-1)d = 1/m ------------------(2)

subtract equation (2) from  equation (1)

tm - tn =>

1/n - 1/m = [(m-1 ) - (n-1)]d

(m-n) / mn = [ m -1 - n + 1] d

(m-n) / m n = (m - n) d

d = (m-n) /mn   divided by (m-n)

d = 1 / mn  sub in equation (1)

a + (m-1) d = 1/n

a + (m -1) /mn = 1/n

a = 1/n - (m-1) / mn

a = 1/ mn  (on solving )

tmn = a + (mn -1) d

      = 1/mn + (mn - 1) /mn

     = (1/mn) + 1 - (1/mn)

tmn = 1

so, mn th term = 1