Question

I want steps of construction of root 3 ....root 5...root 6.....pls its urgent. (Nt the sprical method)

Answer 1

1.      √3
     Draw a right angle triangle with angles = 60 and 30 deg.
     Draw AD horizontal line. Draw a perpendicular line AE.  Now Draw an arc
         on AE with center = A, of length = 1, cutting AE at B. 
   Now with B as the center draw a line of length 2 units, cutting AD at C.  Then
       AC will be of length √3 units.

2.     root 5
    
   Draw a right angle triangle.  Draw AD.  Draw AE perpendicular to AD.  Draw an arc of radius 1 unit, cutting AE at B.   
     With A as the center draw an arc of radius 2 units, cutting AD at C.  Join BC.  it will be of length √5.

3.  root 5

   Draw a right angle triangle ABC...
   Draw AD horizontally.  Draw AE perpendicular to AD.  Then draw an arc of length 2 units, cutting AE at B.  Now with B as the center draw an arc cutting AD at C.  Then  AC will be √5 units long.

4 )    root 6

    Draw AD horizontally.  Draw AE perpendicular to AD.  Cut AE with arc of radius 1, at B.  So AB = 1.  With B as the center draw an arc of radius 2 units, cutting AD at C.  Now AC will be √3 units.    With A as the center, and radius equal to AC, draw an arc cutting AE at F.  So AF = AC = root 3.  Now  join  FD.  length of FD will be √6 units.

Answer 2

this is your answer............