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Given :
AB, CD, EF are concurrent lines, and these lines are passing through O
OF bisects BOF
BOF = 35°
To find :
BOC and AOD
Solution :
Given OF bisects BOD
That BOF = DOF = 35
BOF + DOF + AOD = 180 (Linear pair)
35 + 35 + AOD = 180
70 + AOD = 180
AOD = 180 - 70
AOD = 110
BOC = AOD = 110 (Vertically Opposite Angles are equal)
Therefore AOD = 110°, BOC = 110°
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