Question

I want the answer of 30 A and B

Answer 1

30A)let the number be X

sum of three times the number and 11=32

x+x+x+11=32

3x=32-11

3x=21

X=21/3

X=7

30B)=9/4+23/7

=63+92/28

=155/28

Answer 2

Answer:      A) 7

                   B) $\dfrac{155}{28}$

Step-by-step explanation:

A) Let the number be x

Now according the question that the sum of three times x and 11 is 32 we have

$3x +11 = 32\\\\\Rightarrow3x=32-11\\\\\Rightarrow3x=21\\\\\Rightarrow x=\dfrac{21}{3} =7$

B) Now we have $2\dfrac{1}{4} +3\dfrac{2}{7}$

$2\dfrac{1}{4} +3\dfrac{2}{7} = \dfrac{9}{4} +\dfrac{23}{7}= \dfrac{63+92}{28} =\dfrac{155}{28}$

Hence, answer of 30 A) 7 and B) $\dfrac{155}{28}$