Question

i want the correct answer....no spam....
The enthalpy change (∆H) for the reaction:
N2 (g) +3H2 (g) _______________2NH3 (g)
Is -92.38Kj at 298K.What is U at 298K?
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Answer 1

look, H=U + PV
but PV=nRT
So, H=U+nRT
H is -92.38
T is 298
n is -1
and R is 8.314
put the values

Answer 2

Hope it will help you

Thank you