Question

i want these answers 9th class lines and angles lesson exercise 4.3​

Answer 1

Step-by-step explanation:

6)2a=80°

(corresponding Angles)

=>a=80°/2

=>a=40°

80°+b=180°

(Interior angles on the same side to the transversal)

=>b=180°-80°

=>b=100°

a=40° and b=100°

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7)1=3(vertically opposite angles)

1=5(corresponding angles)

1=9 (corresponding angles)

1=11(alternative interior angles)

2=4(vertically opposite angles)

2=6(corresponding angles)

2=8(alternative exterior Angles)

2=10(corresponding angles)

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8)y=59°(alternative interior angles)

x=60°(corresponding angles)

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9)y+35°+105°=180°(linear angles)

=>y+140°=180°

=>y=180°-140°

=>y=40°

x+105°=180°(interior angles on the same side to the given transversal)

=>x=180°-105°

=>x=75°

x=75° ,y=40°

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10)x+120°=180°(exterior angles on the same side to the transversal)

=>x=180°-120°

=>x=60°

=>x=3y+6(corresponding angles)

=>60°=3y+6

=>3y=60°-6

=>3y=54°

=>y=54°/3

=>y=18°

x=60° ,y=18°

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