Math, asked by riddhee3, 1 year ago

I want this answer with method

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Answered by Anusha755
5
I think it's the answer. I solve it properly
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Answered by BrainlyKing5
6
\underline{\textbf{Hey Mate Here Is Your Answer }}

\underline{\textbf{Given That ...}}

\mathbf{\frac{7}{9} = \frac{63}{x}}

And Now We Need To Find Value Of X ..

Let's Move For Solution..

\underline{\large{\textbf{Solution..}}}

\underline{\textbf{Method - 1 Cross Multiplication}}

Cross Multiplication Is A Method Of Solving An Equation If Both Sides LHS And RHS Have Fraction {only}..

In This Method We Need To Multiply Numerator Of LHS With Denominator Of RHS And Similarly also We Need

To Multiply Denominator Of LHS With Numerator Of RHS..

So By This Method We Have.\longrightarrow

\mathbf{\frac{7}{9}\:= \:\frac{63}{x}}

After Cross Multiplication We Have.\longrightarrow

\mathbf{(7)(x) = (63)(9)}

That Is \longrightarrow

\mathbf {7x = 567} \:

Now Taking 7 To RHS We Have .\longrightarrow

\mathbf {x = \frac{567}{7} }

Therefore We Have .\longrightarrow

\mathbf {x = 81}

\underline{\textbf{Method -2 Simply TakinG Terms From LHS To RHS }}

This Method Is Similar To First Method But in this Method We Are Not Doing Directly We Will Take Each Term

LHS - RHS And Vice-versa.

So By This Method We Have .\longrightarrow

\mathbf{\frac{7}{9} = \frac{63}{x}} \:

Now Taking 9 To RHS We Have.\longrightarrow

\mathbf{7 = \frac{63}{x} \times 9}

As By Taking Any Term From LHS To RHS Or Vice versa The Operation Gets Changed Into Opposite Operation

Now Taking X To LHS We Have ..

\mathbf{7x = {63} \times 9}

That Is .\longrightarrow

\mathbf{7x = 567}

Now Taking 7 to LHS We Have \longrightarrow

\mathbf{x = \frac{567}{7}}

That Is ..

\boxed{\mathbf{X\: = \: 81}}

\underline{\textbf{HENCE The Required Answer Is }}

\boxed{\mathbf{X\: = \: 81}}

\large{\bold{Thanks...}}
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