Question

i want to answer this question by substitute methode

Answer 1

2bx+ay=2ab......(1)
bx-ay=4ab.....(2)
from eq 1
ay=2ab-2bx
y=2ab-2bx/a...3
substituting the value of y in eq 2
bx-a(2ab-2bx/a)=4ab
bx-2a2b+2abx/a=4ab
abx-2a2b+2abx=4ab×a
3abx=4a2b+2a2b
x=6a2b/3ab
x=2a
now putting the value of x in eq 3
y=2ab-2b×2a/a
y=2ab-4ab/a
y=-2ab/a
y=-2b
I think this is your answer