Question

i want to know complete answer of this question this is from motion.

Answer 1

We are assuming that the body is under uniform acceleration here. Then, the total distance d travelled after the first t seconds is given by

d=ut+12at2d=ut+12at2

Where u is the initial velocity and a is the acceleration. We put the values of these quantities for the first 2 seconds:

200=2u+2a200=2u+2a

where u is in cm/s and a is in cm/s/s.

Then at the end of 6 seconds, the total distance travelled is 200+220 = 420 cm. So,

420=6u+18a420=6u+18a

Upon solving, this gives u = 115 cm/s and a = -15 cm/s/s.

So velocity at the end of 7 seconds is given by:

v=u+atv=u+at

= 115 - 105 = 10 cm/s



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