I want to know that how to apply property (x+a) (x+b)
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103.107=(100+3)107
10700+321. =11021
95. 96=5.4=20
(95-4)= 9120
10700+321. =11021
95. 96=5.4=20
(95-4)= 9120
baljinderkhairpa9ufa:
thanks
Answered by
1
i)
![103 \times 107 \\ = (100 + 3)(100 + 7) \\ = (100) {}^{2} + (3 + 7)100 + 3 \times 7 \\ = 10000 + 1000 + 20 \\ = 11021 103 \times 107 \\ = (100 + 3)(100 + 7) \\ = (100) {}^{2} + (3 + 7)100 + 3 \times 7 \\ = 10000 + 1000 + 20 \\ = 11021](https://tex.z-dn.net/?f=103+%5Ctimes+107+%5C%5C++%3D+%28100+%2B+3%29%28100+%2B+7%29+%5C%5C++%3D+%28100%29+%7B%7D%5E%7B2%7D+%2B+%283+%2B+7%29100+%2B+3+%5Ctimes+7+%5C%5C++%3D+10000+%2B+1000+%2B+20+%5C%5C++%3D+11021)
ii)
![95 \times 96 \\ = (100 - 5)(100 - 4) \\ = (100) {}^{2} - (5 + 4)100 - 5 \times - 4 \\ = 10000 - 900 + 20 \\ = 9120 95 \times 96 \\ = (100 - 5)(100 - 4) \\ = (100) {}^{2} - (5 + 4)100 - 5 \times - 4 \\ = 10000 - 900 + 20 \\ = 9120](https://tex.z-dn.net/?f=95+%5Ctimes+96+%5C%5C++%3D+%28100+-+5%29%28100+-+4%29+%5C%5C++%3D+%28100%29+%7B%7D%5E%7B2%7D+-+%285+%2B+4%29100+-+5+%5Ctimes++-+4+%5C%5C++%3D+10000+-+900+%2B+20+%5C%5C++%3D+9120+)
iii)
![104 \times 96 \\ = (100 + 4)(100 - 4) \\ = ( 100) {}^{2} -( 4) {}^{2} \\ = 10000 - 16 \\ = 9984 104 \times 96 \\ = (100 + 4)(100 - 4) \\ = ( 100) {}^{2} -( 4) {}^{2} \\ = 10000 - 16 \\ = 9984](https://tex.z-dn.net/?f=104+%5Ctimes+96+%5C%5C++%3D+%28100+%2B+4%29%28100+-+4%29+%5C%5C++%3D+%28+100%29+%7B%7D%5E%7B2%7D++-%28+4%29+%7B%7D%5E%7B2%7D++%5C%5C++%3D+10000+-+16+%5C%5C++%3D+9984)
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