I want to know what Is answer solved to this question
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1
cross multiply the denominators with the numerators
so
2(a-8)=3(a-3)
2a-16=3a-9
-16+9=3a-2a
-7=a
so
2(a-8)=3(a-3)
2a-16=3a-9
-16+9=3a-2a
-7=a
Answered by
1
MULTIPLY BOTH SIDES BY 6
THE VALUE OF a IS -7
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