Question

i What do you observe from the bar grape about the marks dll term examinations
तtell me step by step


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Answer 1

Answer:

sorry bro I don't know mera answer nahi aya

Answer 2

Answer:

Initially the bullet was at rest inside the barrel and attains a velocity/speed of 100 m/s. The mass given is m and kinetic energy is 100 J. We have to find the mass.

K.E. formula:-

= \boxed{ \rm{ \frac{1}{2} m( {v2}^{2} - {v1}^{2} )}}=

2

1

m(v2

2

−v1

2

)

Basically it's half of the product of its mass and change in velocity. By using this formula,

⇛ K.E = 1/2 m(v² - u²)

⇛ 100 = 1/2 × m × (100² - 0²)

⇛ 200 = 10000 m

⇛ m = 200/10000 kg

⇛ m = 0.020 kg / 20 g

Note:-

Since the units are already in S.I. unit, so I didn't bother having any unit conversion and directly used the S.I. of mass i.e. kg