Question

I WILL DEFINITELY MARK YOU AS BRILLIANT


factorise x³+13x²+32x+20​

Answer 1

Answer:

x³+13x²+32x+20

=(x+1)(x²+12x+20)   [∵, for x=-1, x³+13x²+32x+20=-1+13-32+20=0]

=(x+1)(x²+10x+2x+20)

=(x+1){x(x+10)+2(x+10)}

=(x+1){(x+10)(x+2)}

=(x+1)(x+2)(x+10)

Answer 2

Answer:

X³+13x²+32x+20

=(x+1)(x²+12x+20) [∵, for x=-1,)

x³+13x²+32x+20=-1+13-32+20=0]

=(x+1)(x²+10x+2x+20)

=(x+1){x(x+10)+2(x+10)}

=(x+1){(x+10)(x+2)}

=(x+1)(x+2)(x+10)

Step-by-step explanation:

please mark as branlist