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the i and r would be the same on the surface CD as the medium of change doesn't change for the light's path!
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in the following diagram...
given: <i = 35° and <r = 15°
then ATQ,
sin i/sin r = 'sin i/'sin r
35/15 = 7/3
therefore, <'i = 7° & <'r = 3°
hope you understand...
DarkOverlord:
dude pls send the answer with a diagram... cause there is no q and t
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