CBSE BOARD XII, asked by parakhcmd, 1 year ago

I will mark as brainliest
Find the angle of intersection of the curves x^2 + y^2= 4 and (x – 2)^2 + y^2= 4, at the
point in the first quadrant.
pls answer quickly with full steps no spam

Answers

Answered by Avinashjoge
1

x^2+y^2=4_________(1)

(x-2)^2+y^2=4

x^2-4x+4+y^2=4

x^2-4x+y^2=0________(2)

remaining ans is on photo, it will take some time

answer is 45°

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parakhcmd: sorry bro the correct ans is 60 degrees
parakhcmd: check your answer
Answered by abhisheksureshp916oi
1

The equation x2+y2=4 corresponds to a circle.

From this equation you get y2=4-x2

Substitute this value of y2 in the second equation and you will get a value for x.

Now substitute the value of x in any of the two equation to get the corresponding value of y.

Note: when taking roots, consider only the positive roots as in the first quadrant both coordinates are positive.

Good luck! :')

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