Math, asked by Mathelete, 1 year ago

I will mark as brainliest. please urgent

Attachments:

Answers

Answered by siddhartharao77
2
Given Equation is  x^{2} +  \frac{1}{4 x^{2} } + 1 - 7x -  \frac{7}{2x}

= >  \frac{4x^2 * x^2 - 1 + 1 * 4x^2 - 7x * 4x^2 - 7.2x}{4x^2}

= >  \frac{4x^2 * x^2 - 1 + 1 * 4x^2 - 4 * 7x^2x - 2 * 7x }{4x^2}

= >  \frac{4x^4 - 1 + 4x^2 - 28x^3 - 14x}{4x^2}

(or)

= >  \frac{4x^4 - 28x^3 + 4x^2 - 14x - 1}{4x^2}


Hope this helps!
Similar questions