Question

i will mark as brillant

Answer 1

please match it with your answer.

Answer 2

Given : (2014)^(x + 2015) = (2015)^(x + 2015).

$=> (2014)^x * 2014^{2015} =(2015)^{x} *2015^{2015}$

$=>(\frac{2014}{2015})^x = ( \frac{2015}{2014})^{2015}$

$=> (\frac{2015}{2014}) ^{-x} = (\frac{2015}{2014})^{2015}$

= > -x = 2015

= > x = -2015.

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Now,

Given x^x

= > (-2015)^(-2015).

Therefore, the final answer is Option(D).

Hope it helps!