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Answers
Picture : 1
Let us take the 1st Equation : 3x + 7 = 10
⇒ 3x = 10 - 7
⇒ 3x = 3
⇒ x = 1
But it is given in the Equation solution that x = -1, so this equation needs to be corrected with x = 1
2nd Equation : 5(x + 4) - x = 40
⇒ 5x + 20 - x = 40
⇒ 4x + 20 = 40
⇒ 4x = 40 - 20
⇒ 4x = 20
⇒ x = 5
It is given that the solution for this equation is x = 5 and we got x = 5, so it needs no correction
3rd Equation : (x - 3)/4 = 3
⇒ (x - 3) = 4 × 3
⇒ x - 3 = 12
⇒ x = 15
But it is given in the Equation solution that x = 12 so this equation needs to be corrected with x = 15
4th Equation : 7 = (1/3)x + 5
⇒ (1/3)x = 7 - 5
⇒ (1/3)x = 2
⇒ x = 6
It is given that the solution for this equation is x = 6 and we got x = 6, so it needs no correction
Picture : 2
We know that (6 × 6) = 36 and also (-6 × -6) = 36
⇒ if d² = 36 then the variables which make the equation true are both +6 and -6
⇒ x = (+ or -) 6