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If x + 1/x = under root 5, find the values of x^2+1/x^2 and x^4+1/x^4?
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x+1/x= root 5
(on squaring both side)
x²+1/x²+2=5
x²+1/x²=5–2=3 ans
x²+1/x²=3(again squaring both side)
x4+1/x4+2=9
x4+1/x4=9–2=7
if you have any query then ask.
(on squaring both side)
x²+1/x²+2=5
x²+1/x²=5–2=3 ans
x²+1/x²=3(again squaring both side)
x4+1/x4+2=9
x4+1/x4=9–2=7
if you have any query then ask.
shubhamkumar81:
how
Answered by
6
HOLA! MATE⤵️
☢️SOLUTION ☢️
GIVEN :
⏩ x + 1/x = √5
FIND :
⏩ the values of x² + 1/x²
⏩ x⁴ + 1/x⁴
▶️ x + 1/x = √5
▶️( x + 1/x) = (√5)²
▶️ x² + 1/x² = 5
▶️ x² +1/x² +2 = 5
▶️ x² + 1/x² = 5 - 2
▶️ x² + 1/x² = 3.
then,
⏩ x⁴ + 1/x⁴
▶️( ( x + 1/x)²) ²= (3)²
▶️ x⁴ + 1/x⁴ + 2 = 9
▶️ x⁴ + 1/x⁴ = 9-2
▶️ x⁴ + 1/x⁴ = 7
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