Math, asked by subhikshamrth, 11 months ago

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Answered by binodkjha1972
0

Answer:

Let x=train speed

Let y = car speed 

speed = distance / time 

time = distance / speed 

6 hours 30 minutes = 6.5 hours <== 400 km by train ; 200 km by car 

1/2 hour longer = 7 hours <== 200 km by train ; 400 km by car 

Train time + car time = total time 

400 / x + 200 / y = 6.5 <== two equations and two unknowns 

200 / x + 400 / y = 7 . . . . . . solve for x and y 

400y + 200x = 6.5 xy 

200y + 400x = 7 xy 

400y - 6.5 xy = - 200x 

200y - 7xy = - 400x 

y ( 400 - 6.5x) = -200x 

y ( 200 - 7x) = -400x 

y (6.5x - 400) = 200x 

y (7x - 200) = 400x 

y = 200x / (6.5x - 400) 

y = 400x / (7x - 200) . . . note this equation ... for later use 

. . . since both equal y, the difference is zero 

200x / (6.5x - 400) - 400x / (7x - 200) = 0 

200x ( 7x - 200) - 400x (6.5x - 400) = 0 

1400x^2 - 40000x - 2600x^2 + 160000x = 0 

120000 x - 1200 x^2 = 0 

100 - x = 0 

x = 100 km / h ( trains speed )

y = 400x / (7x - 200) . . . see note above 

y = 400 * 100 / (7 * 100 - 200) 

y = 80 km / h ( car speed)

hope this helps

Answered by SabiRenu
0

Answer :  Hence, the speed of the train is 100km/hr and the speed of the car is 80km/hr.

Step by step Explantation : Let the speed of a train =xkm/hr

 And the speed of a car =ykm/hr

Total distance travelled =600km

According to the question,

If he covers 400km by train and rest by car i.e. (600−400)  =200km

Time take =6 hrs 30min =6+  60 30 ​  =6.5 hrs

If he travels 200km by train and rest by car i.e. (600−200)  =400km

He takes half hour longer i.e. 7 hours

So, total time = train time + car time We know that, time =   speed   distance  ​    ⇒  x 400 ​  +  y 200 ​  =6.5…

(i) ⇒  x 200 ​  +  y 400 ​  =7…

(ii) Let take   x 1 ​  = u and   y 1 ​  =v  400u+200v=6.5⋯

(iii) and 200u+400v=7…

(iv) On multiplying Eq.

(iii) by 2 and Eq.

(iv) by 4, we get 800u+400v=13…

(a) 800u+1600v=28…

(b) On subtracting Eq.(a) from Eq. (b), we get 800u+1600v−800u−400v=28−13 ⇒1200v=15 ⇒v=  1200 15 ​   ⇒v=  80 1 ​

 On putting the value of v in Eq. (iv), we get 200u+400(  80 1 ​  )=7 ⇒200u+5=7 ⇒200u=2 ⇒u=  100 1 ​   So, we get u=  100 1 ​   and v=  80 1 ​   ⇒x=100 and y=80

Hence, the speed of the train is 100km/hr and the speed of the car is 80km/hr.

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