Question

i will mark u as brainlist plz help me
∆ABC is right angled at B. AB=15cm, BC=20 cm with vertices A, B and C as centres area are drawn each of radius 7cm. find the area of the shaded region.​

Answer 1

Answer:

Area of shaded region = area of semicircle AB + area of semi-circle AC - (area of semicircle on side BC) + area of ΔABC

Area of semicircle AB = πr^2 = 22/7 × 3/2 × 3/2

=7.07 sq. units

Area of semicircle AC = πr^2 = 22/7 ×2×2=12.57 sq. units

Area of semicircle BC = πr^2 =π×( BC/2)^2

Now, BC= 4^2 +3^2

[tex] \sqrt{25} [/tex\sqrt{25}

25

=5

∴ Area of semi-circle BC = 22/7 ×(5/2 )^2

=19.64 sq. units.

Area ΔABC=1/2×AB×AC= 1/2×3×4=6 sq. units

Therefore, area of shaded region= 7.07+12.57−19.64+6

= 6 sq. units