Question

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--An object is placed at a diatance of 50cm from a concave lens of focal length 20cm find the nature and position of object?

Answer 1

the length is 50cm because actual length from it is 50

Answer 2

Image is formed of the same size so
50cm = 2f
So focal length = 50/2 = 25 cm
f = 25cm

a. Image formed will be virtual .
Erect .
Larger than the object.
1/v - 1/u = 1/f
1/v = 1/25 + 1/-20
1/v = 4/100 - 5/100
1/v = -1/100
v = -100 cm

b. Image formed will be larger than the object.
Image formed will be real.
Image will be formed beyond 2F on the right side of the lens.
1/v = 1/u + 1/f
1/v = 1/-30 + 1/25
1/v = 5/-150 + 6/150
1/v = -5/150 + 6/150
1/v = 1/150
v = 150cm
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