Math, asked by shivam1247, 1 year ago

i will mark you as brainlist pls help guys

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Answered by siddhartharao77
1

 Given : x = 7 + 5\sqrt{2}


 = > \frac{1}{x} = \frac{1}{7 + 5\sqrt{2}}  * \frac{7 - 5\sqrt{2}}{7 - 5\sqrt{2}}


 = > \frac{7 - 5\sqrt{2}}{(7)^2 - (5\sqrt{2})^2}


 = > \frac{7 - 5\sqrt{2}}{49 - 50}


 = > \frac{7 - 5\sqrt{2}}{-1}


 = > 5\sqrt{2} - 7



Now,


 = > x + \frac{1}{x} = 7 + 5\sqrt{2} + 5\sqrt{2} - 7


 = > 10\sqrt{2}


On squaring both sides, we get


 = > (x + \frac{1}{x} )^2 = (10\sqrt{2} )^2


 = > x^2 + \frac{1}{x^2} + 2 * x * \frac{1}{x}  = 200


 = > x^2 + \frac{1}{x^2} + 2 = 200


 = > x^2 + \frac{1}{x^2} = 198



Hope this helps!






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