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a = first term
d = common difference
let say we get cards like below
a = 1
d = 1
then AP for n terms
1 , 2 , 3 , 4 , 5 , ......n
let say in second case
card are
a=2
d = 1
AP for n terms
2 , 3 ,4 , 5 ,....n+1
case 3
a = 1
d = 2
AP for n terms
1 , 3 , 5, 7 .....2n-1
case 4
a = 2
d = 2
Ap for n terms
2 , 4 , 6 , 8 ..........2n
table
a d AP
1 1 1 , 2 , 3 , 4 , ......n
2 1 2 , 3 ,4 , 5 ,....n+1
1 2 1 , 3 , 5, 7 .....2n-1
2 2 2 , 4 , 6 , 8 ..........2n
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