I WILL MARK YOU BRAINLIEST Why does halving the voltage in a power supply not always halve the current?
Anonymous:
I think u should specify wat type of circuit is it.
Would that have an effect? (Not specified in the question what type it is)
Yeh sure.....if its parellel we use the formula VI or V^2/R (as V same across resistor)and if in series we use I^2R.((I same across resistors). So actually knwing the type of circut matters a lot.
Ah okay thank you
Hmm wlcm.
Answers
Answered by
1
Current is not fixed, its dependent on the resistance which is fixed in this question. So a simple reason is that is the voltage is halved the current is also halved (By Ohm's law).
The power is the product of Voltage times current.
If both are halved then the power after that is only 1/4 of the power.
If the voltage was doubled then the power would be quadrupled.
This “squared” relation between power, voltage, and resistance is easily derived.
Given Ohm’s law V=I * R which also means I = V/R
and P = I * V
the P = V * V / R = V^2/R
please mark answer as brainlist pls
I think its better to ans the ques after knwng its parellel or series combination.
The question didn’t specify this
Answered by
1
Hey!
Ur answer is :-
The simple reason is that is the voltage is halved the current is also halved (By ohm's law). The power is the product of Voltage times current. If both are halved then the power after that is only 1/4 of the power. If the voltage was doubled then the power would be quadrupled.
#riShu;-)
Ur answer is :-
The simple reason is that is the voltage is halved the current is also halved (By ohm's law). The power is the product of Voltage times current. If both are halved then the power after that is only 1/4 of the power. If the voltage was doubled then the power would be quadrupled.
#riShu;-)
Thank you :)
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