Why does halving the voltage in a power supply not always halve the current?
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Answered by
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Current is not fixed, its dependent on the resistance which is fixed in this question. So a simple reason is that is the voltage is halved the current is also halved (By ohm’s law).
The power is the product of Voltage times current.
If both are halved then the power after that is only 1/4 of the power.
If the voltage was doubled then the power would be quadrupled.
This “squared” relation between power, voltage and resistance is easily derived.
Given Ohm’s law V=I * R which also means I = V/R
and P = I * V
the P = V * V / R = V^2/R
The power is the product of Voltage times current.
If both are halved then the power after that is only 1/4 of the power.
If the voltage was doubled then the power would be quadrupled.
This “squared” relation between power, voltage and resistance is easily derived.
Given Ohm’s law V=I * R which also means I = V/R
and P = I * V
the P = V * V / R = V^2/R
Answered by
0
Current is not fixed, its dependent on the resistance which is fixed in this question. So a simple reason is that is the voltage is halved the current is also halved (By Ohm's law).
The power is the product of Voltage times current.
If both are halved then the power after that is only 1/4 of the power.
If the voltage was doubled then the power would be quadrupled.
This “squared” relation between power, voltage, and resistance is easily derived.
Given Ohm’s law V=I * R which also means I = V/R
and P = I * V
the P = V * V / R = V^2/R
kingitaat:
pls mark ans as brainlist
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