I will mark your answer as brainliest.... please answer it and no spams.. please....
A ball is initially moving with a velocity of 0.05 m/s. Its velocity decreases at the rate of 0.05 m/s². How much distance will the ball travel before it starts?
Answers
Answered by
0
its answer is 0.0025
by the third equation of motion
v^2 - u^2=2as
v=0 u=0.05 a=-0.05
0-0.05^2=2*-0.05*s
-0.0025/-0.1=s
s=0.0025
we get s = 0.0025
by the third equation of motion
v^2 - u^2=2as
v=0 u=0.05 a=-0.05
0-0.05^2=2*-0.05*s
-0.0025/-0.1=s
s=0.0025
we get s = 0.0025
zxcbnm:
thanxxxxx brother for correction
Similar questions