I will surely mark your answer as brainliest.....
Factorize: 2x(p²+q²)+4y(p²+q²)
Answers
Answered by
11
‼
2x (p² + q²) + 4y (p² + q²)
= (2x + 4y) (p² + q²)
= 2x (p² + q²) + 4y (p² + q²)
= 2xp² + 2xq² + 4yp² + 4yq²
= 2 ( xp² + xq² + 2yp² + 2yq²)
OR
2x (p² + q²) + 4y (p² + q²)
= (2x + 4y) (p² + q²)
= 2 (x + 2y) ( p² + q² )
2x (p² + q²) + 4y (p² + q²)
= (2x + 4y) (p² + q²)
= 2x (p² + q²) + 4y (p² + q²)
= 2xp² + 2xq² + 4yp² + 4yq²
= 2 ( xp² + xq² + 2yp² + 2yq²)
OR
2x (p² + q²) + 4y (p² + q²)
= (2x + 4y) (p² + q²)
= 2 (x + 2y) ( p² + q² )
Answered by
1
Hey dear!!
Here is yr answer
______________________________
=> 2x(p²+q²) + 4y(p²+q²)
(p²+q²) is common
so,
=> (p²+q²) (2x+4y)
Hope it hlpz....
Here is yr answer
______________________________
=> 2x(p²+q²) + 4y(p²+q²)
(p²+q²) is common
so,
=> (p²+q²) (2x+4y)
Hope it hlpz....
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