Question

I. Write the smallest number which is divisible by both 306 and 657
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Answer 1

SOLUTION

The smallest number which is divisible by any given numbers are their LCM.

Here we have to write the smallest number which is divisible by both 306 and 657

To find the LCM of 306 and 657 , let us perform prime factorization of the numbers :-

306 = 2 × 3 × 3 × 17

​657 = 3 × 3 × 73

Therefore , LCM = 3 × 3 × 2 × 17 × 73

LCM of 306 and 657 = 22338

$\red\bigstar$ So the smallest number which is divisible by both 306 and 657 is  22338

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