Question

I = {x : x is perfect cube 27 < x < 216}
Answer

Answer 1

Sorry I didn't understand please make it clear.....

Answer 2

We given a set builder form of Set I.

We need to find roaster form of set or elements of set I.

Element of Set I are perfect cube between 27 and 216.

Here, 27 is perfect cube with cube root = 3 and 216 is also perfect cube with cube root = 6.

So, we have only number 4 and 5 between 3 & 6.

So, Set I contain Cubes of 4 and 5 that is 64 and 125.

Therefore, I = { 64 , 125 }