Question

i²⁹+i-²⁹ evaluate this question​

Answer 1

Step-by-step explanation:

${i}^{29} + {i}^{ - 29}$

$= {i}^{28} .i \: + \frac{1}{ {i}^{29} }$

$= { {(i}^{2} )}^{14} .i + \frac{1}{( { {i}^{2} )}^{14}.i }$

$= {( - 1)}^{14} .i + \frac{ 1}{ {( - 1)}^{14}.i }$

$= i + \frac{1}{i}$

$= \frac{ {i}^{2} + 1 }{i}$

$= \frac{ - 1 + 1}{i}$

$= \frac{0}{i} = 0$

Answer 2

Answer:

your answer attached in the photo